close

satellite tv assignment

 satellite project Essay

SATELLITE, CELLULAR AND PERSONAL CONVERSATION ASSIGNMENT

=CONTENTS=

PROBLEM NUMBER PAGE NUMBER

1 three or more

2 5

3 six

4 eight

5 12

3. 30 12

3. 31 14

several. 32 18

3. 33 18

a few. 34 twenty

3. 37 24

3. 39 27

3. forty five 29

several. 41 30

1 . A total of 24MHz of BW is allocated to a particular FDD cellular telephone system that uses two 30KHz simplex channels to supply full appartment building voice and control programs. Assume each cell phone user generates 0. 1 Earlangs of targeted traffic. Assume Earlang B is employed. a. Discover the number of programs in each cell for the four-cell recycle system. w. If every cell should be to offer capability that is 90% of ideal scheduling, locate the maximum range of users that could be supported every cell exactly where omnidirectional antennas are used each and every base place. c. What is the stopping probability from the systems in (b) when the maximum number of users are available in the users pool area? d. In the event that each new cell now uses 120° sectoring instead of omnidirectional for each and every base stop, what is the brand new total number of users that may be supported every cell for the same blocking likelihood as in (c)? e. If perhaps each cellular covers five square Kilometers, then just how many members could be reinforced in an city market that may be 50Km 5. 50Km for the case of omnidirectional box station antennas? f. In the event that each cell covers five square Km, then how many clients could be reinforced in an downtown market that may be 50Km * 50Km pertaining to the case of 120 degree sectored antennas? Solution:

a. The FDD cellular mobile phone system is allotted o total bandwidth of 24MHZ. The program uses two 30KHZ simplex channels, as a result,

Funnel bandwidth sama dengan (2*30)KHZ = 60KHZ. Therefore, total number of channels is 24, 000/60 = 4 hundred.

Since were using a 4 cell recycle system, so N sama dengan 4.

Consequently, no of channels per cell sama dengan 400/4 = 100. (Ans)

w. Given that omnidirectional antennas are used in each base station, and each mobile phone generates 0. 1 Erlang of targeted traffic with Erlang-B formula. The cell provides capacity that is certainly 90% of perfect arranging, i. electronic. 90% of 100Erlang = 90 Erlang. Then, in case the maximum number of users end up being Umthen:

Um. Au= 85

Or, 1. (0. 1)= 90

Consequently, Um sama dengan 900 users. (Ans).

c. Once maximum numbers of users can be found, the traffic intensity is definitely 90 Erlang. Number of trunked channels sama dengan 100. Via Erlang-B graph and or chart we can see that probability of blocking for this case is definitely 0. 03. Thus Blocking probability is 3%.

m. If we use 120 degree sectoring, after that total number of channels per sector sama dengan 100/3 =33. 33. Stopping probability sama dengan 3%.

Coming from Erlang N chart, 33 channels and blocking probability of 0. 03 corresponds to traffic depth of twenty-five. 8 Erlang. Thus, Um. Au= 25. 8 (per sector)

Or, Um. (0. 1)= 25. 8

Hence, Um = 258 users/sector.

New total number of users = (258*3) = 774 users. (Ans).

elizabeth. Each cellular covers an area = 5 sq kilometres.

The city market area = 50Km * 50Km = 2500 sq kilometres.

Hence, total number of cells within the market = (2500/5) = 500. We determined that intended for omnidirectional antennas, user per cell sama dengan 900. Therefore total clients that can be supported = (500*900) = 5, 50, 1000. (Ans)

f. In the last part, all of us calculated, count of cells within the marketplace = 500. For a hundred and twenty degree sectored antenna, number of users per cell = 774. Hence total readers that can be supported by the system sama dengan (500*774) sama dengan 3, 87, 000...